Why is the output of this program "CLASS A"? Isn't this determined to be of type B? Doesn't it mean that this->g() should call the B class's version of g?
#include <iostream>
using namespace std;
class A {
private:
void g() {
cout << "CLASS A" << endl;
}
public:
virtual void f() {
g();
}
};
class B : public A {
public:
void g() {
cout << "CLASS B" << endl;
}
};
int main() {
A* a = new B();
a->f();
}
Isn't this determined to be of type B?
No. B
may be the dynamic type, but the static type of *this
is A
within all its member functions.
The member function g
is not virtual, so therefore a call to it uses static binding. In static binding, the dynamic type of the object is irrelevant - only the static type matters. A call to the non-virutal g
within a member function of A
should be a call to A::g
.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.