Say I have the following dictionary
counts =
{(0, 0): {'00': 0, '01': 4908, '10': 0, '11': 5092},
(0, 1): {'00': 0, '01': 5023, '10': 0, '11': 4977},
(1, 0): {'00': 0, '01': 5058, '10': 0, '11': 4942},
(1, 1): {'00': 0, '01': 4965, '10': 0, '11': 5035}}
and I want to sum counts[0,0] and counts [0, 1]to get
idealcounts = {'00': 0, '01': 9931, '10': 0, '11': 10069}
How do I extract the counts[0,r] values and then sum them all up? Thank you for your help.
You can just use collections.Counter and update it with the sub-dictionaries you want:
from collections import Counter
data = {
(0, 0): {'00': 0, '01': 4908, '10': 0, '11': 5092},
(0, 1): {'00': 0, '01': 5023, '10': 0, '11': 4977},
(1, 0): {'00': 0, '01': 5058, '10': 0, '11': 4942},
(1, 1): {'00': 0, '01': 4965, '10': 0, '11': 5035}
}
counts = Counter()
for k in ((0, 0), (0, 1)):
counts.update(Counter(data[k]))
print(counts)
# Counter({'00': 0, '01': 9931, '10': 0, '11': 10069})
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