Python dictionary: sum up numerical and remove 'None' values from nested dictionary and assign results to keys of first level

Question

It might be very simple but at the moment, I just don't find a solution for my problem.

I have a dictionary that looks like this:

list_of_pps = {'pp_coal': {'b_el': 20200},
'sto_simple': {'b_el': 200000},
'pp_gas': {'b_el': 41000},
'cable1': {'b_el2': 9000},
'cable2': {'b_el': 8000},
'pp_oil': {'b_el': 1000},
'pp_lig': {'b_el': 11800},
'pp_chp': {'b_th': None, 'b_el': 30000},
'pp_chp2': {'b_th': 25000, 'b_el': 25000}}

What I want is to sum up all numerical (not None) values on the second level (nested dict) of list_of_pps and assign them to the keys of the first level. This would look like this:

list_of_pps = {'pp_coal': 20200,
'pp_chp': 30000,
'pp_chp2': 50000,
'pp_lig': 11800,
'cable1': 9000,
'pp_gas': 41000,
'cable2': 8000,
'sto_simple': 200000,
'pp_oil': 1000}

I hope this makes it more understandable. What would be the best way to accomplish this?

Thanks in advance!

Answer 1

更新以反映新的问题数据：

clean_pps = {k: sum(filter(None, v.values())) for k, v in list_of_pps.items()}

Answer 2

>>> from pprint import pprint
>>> list_of_pps = dict((key, sum(v for v in value.values() if v is not None)) for key, value in list_of_pps.items())
>>> pprint(list_of_pps)
{'cable1': 9000,
 'cable2': 8000,
 'pp_chp': 30000,
 'pp_chp2': 50000,
 'pp_coal': 20200,
 'pp_gas': 41000,
 'pp_lig': 11800,
 'pp_oil': 1000,
 'sto_simple': 200000}

Answer 3

This is a possible implementation of dict_values . That is, assuming I understand your question correctly.

def dict_values(l):
    return [x for x in l if x is not None]