I have a script that runs main()
and at the end I want to send the contents it has by e-mail. I don't want to write new files nor anything. Just have the original script be unmodified and at the end just send the contents of what it printed. Ideal code:
main()
send_mail()
I tried this:
def main():
print('HELLOWORLD')
def send_email(subject='subject', message='', destination='me@gmail.com', password_path=None):
from socket import gethostname
from email.message import EmailMessage
import smtplib
import json
import sys
server = smtplib.SMTP('smtp.gmail.com', 587)
smtplib.stdout = sys.stdout # <<<<<-------- why doesn't it work?
server.starttls()
with open(password_path) as f:
config = json.load(f)
server.login('me@gmail.com', config['password'])
# craft message
msg = EmailMessage()
#msg.set_content(message)
msg['Subject'] = subject
msg['From'] = 'me@gmail.com'
msg['To'] = destination
# send msg
server.send_message(msg)
if __name__ == '__main__':
main()
send_mail()
but it doesn't work.
I don't want to write other files or change the original python print statements. How to do this?
I tried this:
def get_stdout():
import sys
print('a')
print('b')
print('c')
repr(sys.stdout)
contents = ""
#with open('some_file.txt') as f:
#with open(sys.stdout) as f:
for line in sys.stdout.readlines():
contents += line
print(contents)
but it does not let me read sys.stdout
because it says its not readable. How can I open it in readable or change it to readable in the first place?
I checked all of the following links but none helped:
To send e-mails I am using:
def send_email(subject, message, destination, password_path=None):
from socket import gethostname
from email.message import EmailMessage
import smtplib
import json
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
with open(password_path) as f:
config = json.load(f)
server.login('me123@gmail.com', config['password'])
# craft message
msg = EmailMessage()
message = f'{message}\nSend from Hostname: {gethostname()}'
msg.set_content(message)
msg['Subject'] = subject
msg['From'] = 'me123@gmail.com'
msg['To'] = destination
# send msg
server.send_message(msg)
note I have my password in a json file using an app password as suggested by this answer https://stackoverflow.com/a/60996409/3167448 .
using this to collect the contents from stdout by writing it to a custom stdout file using the builtin function print:
import sys
from pathlib import Path
def my_print(*args, filepath='~/my_stdout.txt'):
filepath = Path(filepath).expanduser()
# do normal print
__builtins__['print'](*args, file=sys.__stdout__) #prints to terminal
# open my stdout file in update mode
with open(filepath, "a+") as f:
# save the content we are trying to print
__builtins__['print'](*args, file=f) #saves in a file
def collect_content_from_file(filepath):
filepath = Path(filepath).expanduser()
contents = ''
with open(filepath,'r') as f:
for line in f.readlines():
contents = contents + line
return contents
Note the a+
to be able to create the file if it already does NOT exist.
Note that if you want to delete the old contents of your custom my_stdout.txt
you need to delete the file and check if it exists:
# remove my stdout if it exists
os.remove(Path('~/my_stdout.txt').expanduser()) if os.path.isfile(Path('~/my_stdout.txt').expanduser()) else None
The credits for the print code are from the answer here: How does one make an already opened file readable (eg sys.stdout)?
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