a = [1,2,1,5]
b = [1,1,5]
c = [a[index] for index in b]
print(c)
and I got this error:
IndexError
Traceback (most recent call last)
<ipython-input-158-e03093b57c86> in <module>
2 b=[1,1,5]
3 index=0
----> 4 c=[a[index] for index in b]
5 c
<ipython-input-158-e03093b57c86> in <listcomp>(.0)
2 b=[1,1,5]
3 index=0
----> 4 c=[a[index] for index in b]
5 c
IndexError: list index out of range
I believe you wanted to do this: (Slight modification of your code)
c = [a[index] for index in range(len(b))]
This iterates over the length of list b, which is [0, 1, 2] as len(b) = 3. And these are valid indexes for list a.
In the above implemenation, the list you are iterating over is [1, 1, 5]. And a[5] does not exist since list a has only 4 elements.
Hope this helps!
The reason you are getting this is error is because your list b
has got the number 5
and your list a
is of length 5 and hence has a maximum index of 4, since indexing starts from 0.
So when you try and grab the value from list a
at index 5
, there is no such value which results in the error: list index out of range
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.