i need to find the sum of each row using vector < vector > int > >
on a matrix that has n columns, and n rows.
for example if this is the imput,
n = 4
1 2 3 4
1 1 1 2
2 2 41 8
3 3 10 2
the output should be
10
5
53
18
this is my code so far:
vector<vector<int>> A;
int n, x;
cin >> n;
for (int i = 0; i < n; ++i)
for(int j = 0; j < n; ++j)
cin >> x, A[i].emplace_back(x);
for(int i = 0 ; i < n ; ++i)
{
int sum = accumulate(A[i].begin(), A[i].end(), 0);
cout << sum << "\n";
}
Also I don t think that my reading of the matrix is good.
If you could help, it would be very appreciated!
Thank you!
To read into a 2D vector, you need to read into a 1D vector for each row, and then add that 1D vector to the 2D vector. You could do something like this:
for (int i = 0; i < n; ++i)
{
std::vector<int> row;
for(int j = 0; j < n; ++j)
{
cin >> x;
row.push_back(x);
}
A.push_back(row);
}
You could even allocate space for the entire 2D vector, and then read directly into the correct positions, like this:
auto A = std::vector<std::vector<int>>(n, std::vector<int>(n, 0));
for (int i = 0; i < n; ++i)
for(int j = 0; j < n; ++j)
cin >> A[i][j];
You could simplify this even further as the comment suggests
auto A = std::vector<std::vector<int>>(n, std::vector<int>(n, 0));
for (auto &row : A)
for(auto &element : row)
cin >> element;
Your code to sum up the rows seems reasonable.
int n, x;
cin >> n;
vector<vector<int>> A(n);
for (int i = 0; i < n; ++i)
for(int j = 0; j < n; ++j)
cin >> x, A[i].push_back(x);
for(int i = 0 ; i < n ; ++i)
{
int sum = accumulate(A[i].begin(), A[i].end(), 0);
cout << sum << "\n";
}
The problem is you are trying to access A[i] when there are no vectors in the vector of vectors
vector<vector<int>> A ----> {}
vector<vector<int>> A(4) ----->{{}{}{}{}} // constructor initializes with 4 empty vectors
now you can access A[i] which returns the ith vector object on which you can do a push_back to insert a element
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