I have 2 lists:
l1 = ['UK', 'GER', 'POL']
and
l2 = ['Germany', 'Poland', 'United Kingdom']
The lists are referring to countries but don't match in order.
Is there a way to match the values in l1
to l2
based on the number of letters in l2
?
So the output is:
dic = {'UK': 'United Kingdom',
'GER': 'Germany',
'POL': 'Poland'}
Something like this may work for you:
#!/usr/bin/env python3
l1 = ['UK', 'GER', 'POL']
l2 = ['Germany', 'Poland', 'United Kingdom', 'Ukraine']
d = {}
for short in l1:
lower = short.lower()
# Match prefix or initials.
matches = [x for x in l2 if
x.lower().startswith(lower) or
''.join(w[0] for w in x.split()).lower() == lower]
if len(matches) == 0:
print('no match', short)
elif len(matches) > 1:
print('ambiguous', short, matches)
else:
d[short] = matches[0]
print(d)
$ ./test.py
ambiguous UK ['United Kingdom', 'Ukraine']
{'GER': 'Germany', 'POL': 'Poland'}
I added "Ukraine" to test handling ambiguous matches.
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