in the code below i want to compute qrad in function of D and L but I think I am misusing the function np.moveaxis causing me to have the following error: numpy.AxisError: source: axis 2 is out of bounds for array of dimension 2 import numpy as np import matplotlib.pyplot as plt
import numpy as np
import matplotlib.pyplot as plt
def plot_with_variating_D ():
l = np.arange(1, 1.5, 0.0005)
d = np.arange(0.005, 0.015, 0.00001)
Eb1 = 3543.75
A1 = 1
A2 = np.pi * (d / 2)
A3 = np.pi
F11 = 0
F21 = 2 * (np.arctan(0.5 / l) * (180 / np.pi)) / 360
F12 = (d * np.pi * F21)
F12p = (((4 / l ** 2) + 4) ** 0.5 - 2) * (l / 2)
F13 = F12p - F12
F14 = 1 - F12 - F13
F23 = 0.5
F24 = 1 - F21 - F23
F34 = F14 / np.pi
rho = 0.7
k = 0.04
pr = 0.7
cp = 1005
myu = 2.4 * 10 ** -5
alpha = 5.68 * 10 ** -5
beta = 1 / 500
Ra = (rho * 9.81 * beta * (500 - 293) * l) / (myu * alpha)
Nu = 0.68 + (0.67 * Ra ** 0.25) / (1 + (0.429 / pr) ** (9 / 16)) ** (4 / 9)
h = Nu * k
J1 = 3543.75 + 0.42 * h * (500 - 295)
a = np.array([[A2*F23,-A2*F23-A1*F13,0], [-0.032-A1*F12-A2*F23,A2*F23,0.032],[A1*F12,A1*F13,0]])
b = np.array([-A1*F13*J1,-A1*F12*J1,7*(Eb1-J1)/3 +A1*F12*J1+A1*F13*J1])
print("b=",b)
x = np.linalg.solve(a,np.moveaxis (b,2,-1))
x = x.T
J2 = x[0]
J3 = x[1]
J4 = x[2]
Eb2 = (((1 - 0.8) / (0.8 * A2)) * ((J2 - J1) * A1 * F12 + ((J3 - J2) * A1 * F13 + (J4 - J2) * A1 * F24))) + J2
qrad = (Eb2 - J2) / ((1 - 0.8) / (0.8 * A2))
return qrad
plot_with_variating_D()
I believe you have two problems.
When you add 0, 0.032, and 0 to entry in the lists passed to construct a, you are not matching the dimension of the other terms. You should use np.zeros(len(l)) and 0.032 * np.ones(len(l)).
If my understanding that you want to solve the 3 x 3 system of equations for the 1000 steps in your arange is correct, you want to move the last axis to the front, so for both a and b, move axis -1 to 0. eg "np.moveaxis(a, -1, 0)".
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