Given the following data:
dt = pd.DataFrame({"file": ["a", "a", "b", "b"], "val": [0, 1, 1, 2]})
which looks as
file val
0 a 0
1 a 1
2 b 1
3 b 2
I would like to repace 0
with 2
where file == 'a'
.
The final result being:
file val
0 a 2
1 a 1
2 b 1
3 b 2
Let us try
dt.loc[dt.file.eq('a')&dt.val.eq(0),'val']=2
dt
file val
0 a 2
1 a 1
2 b 1
3 b 2
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