i am first to this site. I want to split a string without the characters that matched in regex of string split method in java.
The string for splitting is (for eg.): "conditional&&operator and ampersand&Symbol."
My regex-expression for spit is: "[^\\&]\\&[^\\&]"
My expectation is: [conditional&&operator and ampersand, Symbol]
But, the output is: [conditional&&operator and *ampersan, ymbol*]
The code i used is:
String s = "conditional&&operator and ampersand&Symbol.";
String[] sarr = s.split("[^\\&]\\&[^\\&]");
System.out.println(Arrays.toString(sarr));
So, please tell me what regex i should use to get the expected output, that is without the additional characters removed.
Your question is very similar to this one .
What you need is a negative look-behind . In your case, you could use something like:
String s = "conditional&&operator and ampersand&Symbol.";
String[] sarr = s.split("(?<!&)&(?!&)");
System.out.println(Arrays.toString(sarr));
// output: [conditional&&operator and ampersand, Symbol.]
I suppose it's impossible to split your string by regex as you wish. The problem is that [^\\&]\\&[^\\&]
matches 3 characters -> d&S
and it splits by 3 characters, so you have them removed. You can use Pattern
and Matcher
to split a string in this way:
String s = "conditional&&operator and ampersand&Symbol.";
final Matcher matcher = Pattern.compile("[^&]&[^&]").matcher(s);
if (matcher.find()) {
final int indexOfMatchStart = matcher.start();
final String firstPart = s.substring(0, indexOfMatchStart + 1); // + 1 to include first symbol of RegEx
final String secondPart = s.substring(indexOfMatchStart + 2); // + 2 to skip &
System.out.println(firstPart + secondPart); // will print conditional&&operator and ampersandSymbol.
}
Try this,
Long code but Basic logic.
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class B {
public static void main(final String[] args) {
final String x = "conditional&&operator and ampersand&Symbol.";
final String mydata = x;
String delimString = "";
final Pattern pattern = Pattern.compile("[^\\&]\\&[^\\&]");
final Matcher m = pattern.matcher(mydata);
while (m.find()){
delimString = m.group(0);
}
final String[] result = x.split(delimString); // Split using 'd&S'
final String[] conResult = delimString.split("&"); //Split d&S in d and s
System.out.println(result[0]+""+conResult[0]); // append d at the end of string
System.out.println(conResult[1]+""+result[1]); // append s at the start of string
}
}
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