Ignoring the newline character while splitting the multiline string

Question

I have a string like below

s = '''printf("\nFloat value is %f \n", flt);
printf("Integer value is %d\n" , no);
printf("Double value is %lf \n", dbl);
printf("\nOctal value is %o \n", no);
printf("Hexadecimal value is %x \n", no);
return 0;'''

I want to split the string. I used splitlines() But it's not giving the output I'm expected. It also splitting the string if it contain \n in middle of the string. What i want is I want to ignore the newline characters in middle of the strings while splitting the string. Is there any way can I solve this without using the files.

for line in s.splitlines():
    #line = somfunction(line)
    print(line)

Output of above code

printf("
Float value is %f 
", flt);
printf("Integer value is %d
" , no);
printf("Double value is %lf 
", dbl);
printf("
Octal value is %o 
", no);
printf("Hexadecimal value is %x 
", no);
return 0;

Expected Output:

printf("\nFloat value is %f \n", flt);
printf("Integer value is %d\n" , no);
printf("Double value is %lf \n", dbl);
printf("\nOctal value is %o \n", no);
printf("Hexadecimal value is %x \n", no);
return 0;

Answer 1

You can achieve the desired result using a string raw notation in your s definition.

s = r'''printf("\nFloat value is %f \n", flt);
printf("Integer value is %d\n" , no);
printf("Double value is %lf \n", dbl);
printf("\nOctal value is %o \n", no);
printf("Hexadecimal value is %x \n", no);
return 0;'''

Notice the r in leading of string. In python this mean a string raw.

Here is the documentation

Answer 2

Try this

s = r'''printf("\nFloat value is %f \n", flt);
printf("Integer value is %d\n" , no);
printf("Double value is %lf \n", dbl);
printf("\nOctal value is %o \n", no);
printf("Hexadecimal value is %x \n", no);
return 0;'''

for line in s.splitlines():
    print(line)