I need to remove all the objects within array who meet the conditions i will show down below. I'll let here the documents and an example of what i've done.
//document 1
{
"_id" : ObjectId("5ec73abebd7e4d618a057350"),
"code" : "X20",
"title" : "Full stack developer",
"location" : "Paris",
"date" : ISODate("2020-05-22T02:36:46.272Z"),
"candidates" : [
{
"name" : "David",
"last_name" : "Broncano",
"telephone" : "642025552",
"email" : "david@gmail.com"
},
{
"name" : "Pablo",
"last_name" : "Claros",
"telephone" : "628721784",
"email" : "pablo@gmail.com"
}
]
}
// document 2
{
"_id" : ObjectId("4ec73abebd7e4d618a057350"),
"code" : "X50",
"title" : "Full stack developer",
"location" : "Madrid",
"date" : ISODate("2020-05-22T02:36:46.272Z"),
"candidates" : [
{
"name" : "Maria",
"last_name" : "Mars",
"telephone" : "642024582",
"email" : "dasd@gmail.com"
},
{
"name" : "Pablo",
"last_name" : "Claros",
"telephone" : "628721784",
"email" : "pablo@gmail.com"
}
]
}
So i need to remove all the candidates where location is Madrid.I have done this but it removes the field. Is it possible to just remove the content of it using $pull or something?
db.offers.update(
{ location : "Madrid"},
{
$unset:{
"candidates":""
} } ,
{
multi : true
}
)
According to my understanding, you need to just clear the candidates
array and maintain that as candidates: []
. For this, you can use use $set
operator to set candidates
to []
based on your condition
db.offers.update({ location : "Madrid"}, { $set:{ "candidates": [] } } , { multi : true })
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