How to sort a list by a specific index

Question

list1=[('Oliver', 75, 180), ('Jack', 90, 190), ('Harry', 75, 175), ('Jacob', 60, 175), ('Charlie', 80, 180), ('Thomas', 70, 180)]

sorted(list1 , key = itemgetter(2 , 1) , reverse=True)

i wanted if persons height the same the person with less weight printed above my code output:

[('Jack', 90, 190), ('Charlie', 80, 180), ('Oliver', 75, 180), ('Thomas', 70, 180), ('Harry', 75, 175), ('Jacob', 60, 175)]

my desire output:

[('Jack', 90, 190), ('Thomas', 70, 180),('Oliver', 75, 180),('Charlie', 80, 180), ('Jacob', 60, 175), ('Harry', 75, 175)]

i use python3

Answer 1

You can try

sorted(list1 , key = lambda x: (x[2], -x[1]) , reverse=True)

Output

[('Jack', 90, 190),
 ('Thomas', 70, 180),
 ('Oliver', 75, 180),
 ('Charlie', 80, 180),
 ('Jacob', 60, 175),
 ('Harry', 75, 175)]

This will sort the list by the highest height and the lowest weight in case of the same height.