I'm working on an assignment that requires me to use "const unsigned char &fret" as input for a method. I have
void fretThing(const unsigned char &fret)
{
char div = fret / 12;
printf("%d\n", div);
}
but when I run the program, div = 0. I believe this is because char converts the number into an int, but when i try to cast to a double, it still does not work.
Is there any way to convert char to double?
when fret = 12, div =1. but when fret is not a multiple of 12, it returns 0.
char div = added / 12;
depending on the type of added
this probably is an integer divison, since 12 is an literal of type int
. You should use a double
-literal 12.0
here. But the assignement to char div
would truncate the result anyway, so change this to a double
. Lastly you want to print this with the correct format specifier %f
. So you get something like this:
void fretThing(const unsigned char &fret)
{
double div = fret / 12.0;
printf("%f\n", div);
}
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