Regex to match string inside curly braces inside square brackets

Question

var q = '{[{main}(other data)][{data}(other data)][{address}(other data)]}';

var qm = q.match(/\[(.*?)\]/g);  

console.log(qm);

The above regex returns text that's between parenthesis.

Eg:

 [{data}(other data)]

How can the above Regex be rewritten so I supplied a string like 'data' it would return [{data}(other data)] . ie the part with parenthesis that contains the string in curly braces.

Answer 1

Matches string inside the curly brace

\[{data}\(.*?*\)\]

Regex Demo

 var q = '{[{main}(other data)][{data}(other data)][{address}(other data)]}'; var qm = (str) => q.match(new RegExp(`\\[{${str}}\\(.*?\\)\\]`, 'g')); console.log(qm('data'));

Matches string inside the curly brace and parenthesis

\[{data}\(.*?data[^)]*\)\]

Regex Demo

 var q = '{[{main}(other data)][{data}(other data)][{address}(other data)]}'; var qm = (str) => q.match(new RegExp(`\\[{${str}}\\(.*?${str}[^)]*\\)\\]`, 'g')); console.log(qm('data'));

Answer 2

Using your qm variable, you can iterate over the matches and test for the string between the first curly braces like so:

 var q = '{[{main}(other data)][{data}(other data)][{address}(other data)]}'; var qm = q.match(/\[(.*?)\]/g); for (let e of qm) if (e.match('\{([^\)]+)\}')[1] == "data") console.log(e);