Following on from a previous question , in which i have a table called orders with information regarding the time an order was placed and who made that order.
order_timestamp user_id
-------------------- ---------
1-JUN-20 02.56.12 123
3-JUN-20 12.01.01 533
23-JUN-20 08.42.18 123
12-JUN-20 02.53.59 238
19-JUN-20 02.33.72 34
I would like to calculate a daily rolling count of the number of days a user made an order in a past 10 days. For example, in the last 10 days from the 20th June, user 34 made an order on 5 of those days. Then in the last 10 days from the 21st June, user 34 made an order on 6 of those days
In the end the table should be like this:
date user_id no_of_days
----------- --------- ------------
20-JUN-20 34 5
20-JUN-20 123 10
20-JUN-20 533 2
20-JUN-20 238 3
21-JUN-20 34 6
21-JUN-20 123 10
How would the query be written for this kind of analysis? Please let me know if my question is unclear/more infor is required. Thanks to you in advancement.
You can use window functions for this. Start by getting one row per user per day. And then use a rolling sum:
select day, user_id,
count(*) over (partition by user_id range between interval '10' day preceding and current row)
from (select distinct trunc(order_timestamp) as day, user_id
from t
) t
Assuming that a user places one order a day maximum, you can use window functions as follows:
select
t.*,
count(*) over(partition by user_id order by trunc(order_timestamp) range 10 preceding) no_of_days
from mytable t
Otherwise, you can get the distinct orders per day first:
select
order_day,
user_id,
count(*) over(partition by user_id order by order_day range 10 preceding) no_of_days
from (select distinct trunc(order_timestamp) order_day, user_id from mytable) t
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