remove only numbers between brackets from a string

Question

I have strings, and I need to remove only numbers inside brackets (remove brackets too) from this:

str = "1.25 (10), 1.5 (148), 1.25 (24)"

to this:

"1.25, 1.5, 1.25"

Answer 1

Try:

import re

x = "1.25 (10), 1.5 (148), 1.25 (24)"

x=re.sub(r'\s*\(\d+\)\s*', '',x)

Outputs:

>>> x

1.25, 1.5, 1.25

Answer 2

Use:

str = "1.25 (10), 1.5 (148), 1.25 (24)"
a=[i for i in str.split(" ") if ("(" not in i)]
str=",".join(a)
print(str)

Answer:

1.25,1.5,1.25 

Answer 3

welcome to Stack Overflow

You can use regex like this:

import re
str = "1.25 (10), 1.5 (148), 1.25 (24)"
new_str = re.sub("\s\([0-9.]+\)", "", str)

The regex command looks for patterns starting with a space followed by a number inside a bracket and replaces it with an empty string.

Answer 4

I tried by getting the brackets and items inside the it and thereafter remove it

---

import re

string = "1.25 (10), 1.5 (148), 1.25 (24)"
txt = string.split(',')
clear = ''
for i in txt:
    clear += re.sub('\(.*\)', '', i)

print(clear.replace('  ', ', '))