How do I use list comprehension to find the smallest value per column?

Question

I have the following list:

List = 
[(1000, 1500),
 (2000, 2500), 
 (900, 3000)]

I want to find the smallest value for each column from the list.

Result = (900, 1500)

How do I use list comprehension to achieve this?

Answer 1

You don't need list comprehensions here, they don't really apply. You could do

Result = (min(List, key=lambda a: a[0])[0], min(List, key=lambda a: a[1])[1])

Answer 2

This will do it, although it doesn't use list comprehension:

list(map(min, zip(*List)))

[900, 1500]

zip(*List) will transpose the list, and the map function will find the minimum of the two elements.

Answer 3

As the previous answer said, you don't really need list comprehension. But in case you really do, you could do something like:

Result = (min([a[0] for a in List]), min([a[1] for a in List]))