I have two tables: T1 = Suppliers, T2 = Additional_data.
T1 Suppliers columns: id, name, code, etc.
Values:
123 | Supplier1 | 10000
124 | Supplier2 | 10001
125 | Supplier3 | 10002
T2 Additional_data columns: id, supplier_id, additional_category_name, value
Values:
334 | Supplier1 | Street | Flower Street
335 | Supplier1 | Bank | National Bank
336 | Supplier2 | Street | Different Street
337 | Supplier2 | Bank | National Country Bank
338 | Supplier2 | VAT_NUMBER | DE23231231
339 | Supplier3 |Street | This Street
340 | Supplier3 |Leader | John M
341 | Supplier3 | VAT_NUMBER | DE12312311
I have the following query:
SELECT s.Code, s.Name, ad.additional_category_name as ADDITIONAL_CATEGORIES, ad.value
FROM ADM_SUPPLIER s LEFT OUTER JOIN
ADM_SUPPLIER_ADDITIONAL_DATA ad
on s.ID = ad.supplier_id;
This gives me all of the suppliers, even if they don't have a VAT_NUMBER in additional_data:
CODE | NAME | ADDITIONAL_CATEGORIES | VALUE
10000 Supplier1 Street Flower Street
10000 Supplier1 Bank National Bank
10001 Supplier2 Street Different Street
10001 Supplier2 Bank National Country Bank
10001 Supplier2 VAT_NUMBER DE23231231
10002 Supplier3 Street This Street
10002 Supplier3 Leader John M
10002 Supplier3 VAT_NUMBER DE12312311
As you can see, not all suppliers have the same additional categories. But I am interested in getting a list of all the suppliers and their VAT_NUMBER. If VAT_Number is empty, then 'N/A' can be added:
Desired output:
CODE | NAME | VAT_NUMBER
10000 Supplier1 N/A
10001 Supplier2 DE23231231
10002 Supplier3 DE12312311
Please let me know how to achieve this.
Thank you!
Just filter the left join
:
select s.code, s.name, coalesce(ad.value, 'N/A') as vat_number
from adm_supplier s
left outer join adm_supplier_additional_data ad
on ad.supplier_id = s.id
and ad.additional_category_name = 'VAT_NUMBER'
On your final result use the below query using group by and case to get the desired result.
SELECT CODE, NAME,
COALESCE(MAX(CASE WHEN ADDITIONAL_CATEGORIES = 'VAT_NUMBER' THEN VALUE END), 'N/A') AS VALUE
FROM Table1 A GROUP BY CODE, NAME;
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