When I run this program, I need the part where it says example " cans needed 3.0" I need it to only say the integer.
public class PaintEstimator {
public static void main(String[] args) {
// Create the Scanner object scnr
Scanner scnr = new Scanner(System.in);
// Declare the identifiers
double wallHeight;
double wallWidth;
double wallAera;
double gallonPaint = 350;
int paintNeeded;
// Prompt user for and input wall's height and width; and then display them
System.out.println("Enter wall height (feet) :");
wallHeight = scnr.nextInt();
System.out.println("Enter wall width (feet) :");
wallWidth = scnr.nextInt();
System.out.println("Wall height is: " + wallHeight + " and Wall width is: " + wallWidth);
// Calculate and output wall area
wallAera = wallHeight * wallWidth;
System.out.println("Wall area: " + wallAera + "square feet");
// Calculate and output the amount of paint in gallons needed to paint the wall
System.out.println("Paint needed: " + (wallAera / gallonPaint) + " gallons");
// Calculate and output the number of 1 gallon cans needed to paint the wall, rounded up to nearest integer
System.out.println("Cans needed: " + Math.ceil(wallAera / gallonPaint) + " can ( s )");
// Calculate and output the cost of painting the wall.
double costPaint = Math.ceil(wallAera / gallonPaint) * 45.0;
System.out.println("Cost to paint the wall: $" + costPaint);
}
}
您可以像已经在做的那样舍入/限制它,然后将其转换为 int:
System.out.println("Cans needed: " + (int) Math.ceil(wallAera / gallonPaint) + " can ( s )");
There are 3 basic methods for change a double to an integer.
Where var-name is an integer and var-name1 is a double.
Method 1: Type-casting
Example:
int var-name = (int) var-name1;
Method 2: Rounding
Example:
int var-name = Math.round(var-name1);
Method 3: Double.intValue
Example:
int var-name = Double.intValue(var-name1);
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