SQL Partitioning, how to select a record in the partitioned group that meets certain criteria?

Question

I have a query. This query is:

select Q1.* from (
    select
        a.CreatedDate as KynectCreatedDate,
        a.FirstName,
        b.CaseStatusCode,
        a.Id as ContactId,
        a.Email as EmailAddress,
        a.MobilePhone,
        row_number() over (partition by a.Email order by b.CaseStatusCode desc) as row
    from
        ent.Contact_Salesforce a
    left join
        ent.SOMETABLE_Contact_Shared c on a.Email = c.Email
    left join
        ent.SOMETABLE_Case_Shared b on c.IndividualId = b.IndividualId and c.CaseNumber = b.CaseNumber
    where a.Email = 'aaa@aaa.com') Q1
where Q1.row = 1

Here's what I want. The group of records that come back as defined in the partition by clause - say there's 3 that come back (row number 1, 2, 3). If CaseStatusCode is "AC" on any of them, PICK THAT RECORD OUT OF THE GROUP. Otherwise, DOESN'T MATTER WHAT RECORD I PICK. Right now, the query is just picking the first record in the group ( where Q1.row = 1 ). I'm having a hard time figuring out how to do this. Any ideas?

Answer 1

将该信息按以下order by ：

    row_number() over (partition by a.Email order by (case when b.CaseStatusCode 'AC' then 1 else 2 end) as row