My friends and I are quite struggling with this task. In any other language this would be easy.
We tried converting the tree into a list, remove an element and then building a tree. The build from list to tree building part we have no clue how to do.
How would I go about it with this tree:
tree(1, [tree(6, [tree(7, [])] ),
tree(3, []),
tree(2, [tree(4, []),
tree(5, [])])
])
Would be immensely grateful for any nudges or solutions.
Prolog variables are immutable - their value cannot be changed. So, if you want to change a tree say 3-way tree, you have a predicate that state the desired change.
A simple non-recursif case to replace specific nodes with new values:
replace_left_node(tree(_,B,C), NewNode, tree(NewNode, B, C).
replace_right_node(tree(A,B,_), NewNode, tree(A, B, NewNode).
replace_middle_node(tree(A,_,C), NewNode, tree(A, NewNode, C).
For a recursif case, you have to specify the change in greater detail. Say, in a tree with left & right sub trees and node value in the middle argument, replace node values having the value a by the value b, such as:
replace(a, b). % replace the value a by value b
replace(X, X) :- X \= a. % otherwise use the same value unchanged
The recursive situation is to do the same to the Left and Right sub-trees.
replace_recursively(terminal, terminal) % this is the tree leaf
replace_recursively(tree(L, V, R), tree(L1, V1, R1)) :-
replace(V, V1), % handle the node value
replace_recursively(L, L1), % handle left sub-tree
replace_recursively(R, R1). % handle right sub-tree
Does this answer your question? What else do you need?
OK, with the example you gave in the comment, I understand better. I give you an example for removing the node with given value Elm. This is a double recursion, one for handling the functor tree and another for handling lists.
remove_elem_from_tree(Elm, tree(V, Nodes), tree(V,Nodes1) ):-
Elm \= V,
remove_elem_from_list(Elm, Nodes, Nodes1).
remove_elem_from_list(_, [], []).
remove_elem_from_list(E, [X|Xs], [Y|Ys]) :-
remove_elem_from_tree(E, X, Y), !,
remove_elem_from_list(E, Xs, Ys).
remove_elem_from_list(E, [_|Xs], Ys) :-
remove_elem_from_list(E, Xs, Ys).
So example run is: remove the node 4
?- remove_elem_from_tree(4, tree(1,
[ tree(6, [tree(7, [])]),
tree(3, []),
tree(2, [tree(4, []),tree(5, [])])
]
), Result).
Result = tree(1,[tree(6,[tree(7,[])]),tree(3,[]),tree(2,[tree(5,[])])])
The node 4 was under node 2 in the given tree. It is removed and node 2 now has the only child node 5.
Does this answer help you and your friends?
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