Proper way to handle file open and file close Exception

Question

Please see this implementation:

@staticmethod
    def read_json_file__(file):
        reports = []
        try:
            with open(file) as json_file:
                data = json.load(json_file)
                for d in data:
                    # Do my stuff...
            try:
                json_file.close()
            except IOError as ex:
                raise Exception(ex)
            return reports
        except FileNotFoundError as ex:
            raise Exception('File \'{f}\' does not exist.'.format(f=ex.filename))
        except Exception:
            raise

I try to find the way to handle Exceptions so I handle file open Exception ( FileNotFoundError ) and file close Exception ( IOError ) and also add Generic Exception and raise it to caller method. Is this correct way to handle Exception ?

Answer 1

当使用with open(file) as json_file ，你不需要关闭，但如果你使用json_file = open(file)你需要关闭它（使用json_file.close() ）。