So far, I managed to find if ONE letter is in ANY given string. However, I cannot manage to ask for multiple conditions like 'a' && 'e' && 'i'... In a way that all of those letter need to be in the string so the echo "Vowel found" gets out.
I have tried with stristr, strpos... and so far my best guess was deprecated so I couldn't use it. My last resource, which didn't work anyway, was to nest if conditions to make it work; also tried with arrays with no positive result.
$string = 'murcielago'; // a word with 5 vowels
if (stristr($string, 'a') == TRUE) {
echo 'Vowel found';
} else {
echo "Vowel not found";
}
This is my code for ONE string or letter to be found in the original given string.
It made me think further! Got it.
$string = "murcielago";
if (strpos($string,'a') && strpos($string,'e') && strpos($string,'i') && strpos($string,'o') && strpos($string,'u') == true)
{
echo "nailed it";
} else {
echo "No vowels for you";
}
´´´
I wonder if there is any way to make all the conditions into one since I am still using the same strpos function.
Try using a regex and preg_match
<?php
//Enter your code here, enjoy!
$string = 'murcielago';
// This will echo "vowel found"
if(preg_match( '`[aeiouy]`', $string)){
echo "vowel found\n";
}
$string2 = 'bcdfgplk';
// This won't echo anything
if(preg_match( '`[aeiouy]`', $string2 )){
echo "vowel not found\n";
}
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