I have a case that when parsing multiple XML files, actually I want the result of the parsing XML to become a single dictionary list instead of multiple dictionary lists.
import glob
from bs4 import BeautifulSoup
def open_xml(filenames):
for filename in filenames:
with open(filename) as fp:
soup = BeautifulSoup(fp, 'html.parser')
parse_xml_files(soup)
def parse_xml_files(soup):
stringToListOfDict = []
.
.
.
for info in infos:
dict = {}
types = info.find_all('type')
values = info.find_all('value')
for type in types:
dict[type.attrs['p']] = type.text
stringToListOfDict.append({'Date': Date, 'Time': Time, 'NodeName': node})
for value in values:
for result in value.find_all('x'):
label = dict[result.attrs['y']]
value = result.text
if label:
stringToListOfDict[-1][label] = value
print(stringToListOfDict)
def main():
open_xml(filenames = glob.glob("*.xml"))
if __name__ == '__main__':
main()
With my code above, it always produces two dictionary lists (eg for two XML files) below:
[{'Date': '2020-11-19', 'Time': '18:15', 'NodeName': 'LinuxSuSe','Speed': '16'}]
[{'Date': '2020-11-19', 'Time': '18:30', 'NodeName': 'LinuxRedhat','Speed': '16'}]
The desired output should be one list with two dictionaries only:
[{'Date': '2020-11-19', 'Time': '18:15', 'NodeName': 'LinuxSuSe','Speed': '16'},{'Date': '2020-11-19', 'Time': '18:30', 'NodeName':'LinuxRedhat','Speed': '16'}]
Really appreciated your feedback
print()
is used only to send information on screen and it will not join all results in one list.
Your name parse_xml_files
is missleading because it parses single file, not all files. And this function should use return
to send result for single file and in open_xml
you should get this result add to one list - and then you should have all files in one list.
Not tested:
def open_xml(filenames):
all_files = []
for filename in filenames:
with open(filename) as fp:
soup = BeautifulSoup(fp, 'html.parser')
result = parse_xml_file(soup) # <-- get result from parse_xml_file
all_files += result # <-- append result to list
print(all_files) # <-- display all results
def parse_xml_file(soup):
stringToListOfDict = []
# ... code ...
for info in infos:
dict = {}
types = info.find_all('type')
values = info.find_all('value')
for type in types:
dict[type.attrs['p']] = type.text
stringToListOfDict.append({'Date': Date, 'Time': Time, 'NodeName': node})
for value in values:
for result in value.find_all('x'):
label = dict[result.attrs['y']]
value = result.text
if label:
stringToListOfDict[-1][label] = value
#print(stringToListOfDict)
return stringToListOfDict # <-- send to open_xml
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