I have created a function that takes an array and outputs another array. So I have declared the result array (which will be the output) as null cause the size varies and depends on the inputted array. (for eg. if I enter an array of integers and then I want to output the array containing even numbers from that array). So I will be using for or while loops and I want to know that how I can add the integer to that null array. I tried but I get a null pointer exception that says cannot store to int array cause "array" is null.
sorry but I can't use more advanced techniques cause I am new to java (I need to make this without using arraylist library as I am learning coding I found those type of questions which tries to make you perfect in i specific topic and then they take you to next step so u can be more prepared)
I am using this code and I want to know that add an element to my result array or should I initialized it as null or something else cause the size depends on inputted array in this code I am getting null pointer exception
public static int[] even(int[] numbers) {
int[] result = null;
int even = 0;
int i = 0;
int a = 0;
while (i < numbers.length) {
if (numbers[i] % 2 == 0) {
even = numbers[i];
result[a] = even;
a++;
}
i++;
}
return result;
}
The array's size needs to be initialized. If you want dynamic storage, read about List
and Collection
.
Here, if you still want to use array, you need the count.
int a = 0;
while (i < numbers.length) {
if (numbers[i] % 2 == 0) {
a++;
}
i++;
}
Then after this, you can initialize it as int[] result = new int[a]
;
public static int[] even(int[] numbers) { int[] result = null; int j = 0; int a = 0; while (i < numbers.length) { if (numbers[j] % 2 == 0) { a++; } j++; } result = new int[a]; int even = 0; int i = 0; int b = 0; while (i < numbers.length) { if (numbers[i] % 2 == 0) { even = numbers[i]; result[b] = even; b++; } i++; } return result; }
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.