Convert text file to hex - New Line problem

Question

I'm trying to convert a text file to hexadecimal and then back to a text again. It works well as long as I do not use new line.

The first function take te filename and returns a list with integers that represents each letter.

    block = []
    file = open(filename, 'rb')
    content = file.read()
    
    hexstring = binascii.hexlify(content)

    for i in range(0,len(hexstring),2):
        block.append(int(hexstring[i:i+2], base=16))

    return block

This is how I convert back to plaintext.

for i in range(len(stringList)):
    tmp = stringList[i]
    for j in range(len(tmp)):
        hexString = str(hex(tmp[j]))
        hexString = hexString.replace('0x', '') 
        pt = bytearray.fromhex(hexString).decode()
        plainText.append(pt)

The code is awful but works as long as I do not have a new line. Then I get the following error.

pt = bytearray.fromhex(hexString).decode()
ValueError: non-hexadecimal number found in fromhex() arg at position 1

Answer 1

try using codecs modules

import codecs def encode(): with open(file='sample.txt') as file: text = file.read() return codecs.encode(bytes(text, encoding='utf-8'), "hex") def decode(encodedString): return codecs.decode(encodedString, 'hex') a = encode() b = decode(a) print(a) print(b)