Python parse only digit

Question

Hi I want to parse only digit, for example I parse numbers of users sessions last 5 min, userSes = "12342 last 5 min", I want to parse only 12342 (this number change every 5 min), but when I parse this data result is 12342 and 5 ( this number is "from last 5 min " 's number) can any one help me?

x= ('12342 from last 5 min ')
print(''.join(filter(lambda x: x.isdigit(),x)))

Answer 1

You can use regex:

import re

x = '12342 from last 5 min '
n_sessions = int(re.findall('^(\d+).*', x)[0])
print(n_sessions)

^(\d+).* looks for a number ( \d+ ) at the start of the string ( ^ ) before the space and everything else ( .* ).

If your string is consistent

n_sessions = int(x.split()[0])

should be enough.

Answer 2

parsed_list = [item for item in x.split(' ')[0] if item.isdigit()]
print(''.join(parsed_list))