How to execute a python file in command with different arguments

Question

I have a python file which accept four arguments as input. I run the python file in Anaconda environment by this command.

python "\python.py" --arg1 "account" --arg2 "userid" --arg3 "action" --arg4 "filename"

May I know any ideas to execute this command for many times with different userid and filename arguments? Any batch file could help to do this?

Thanks for your help!

Answer 1

One way actually involves python - make a script that activates the original script with different arguments each time, with something like that:

import os  # for os.system, which executes the command in a subshell.

list_of_args = [[1,2,3,4],[a,b,c,d],...,]

for item in list_of_args:
    os.system(f'python "\python.py" --arg1 {item[0]} --arg2 {item[1]} --arg3 {item[2]} --arg4 {item[3]}')

Another option using the same "storage" method is, but with a different string formatting way is:

for item in list_of_args:
    os.system('python "\python.py" --arg1 {} --arg2 {} --arg3 {} --arg4 {}'.format(*item))

There are other options, including user input or importing data from a file(an excel sheet for example), etc, even not using python. This is just a simple example that stays in what you've already delved a bit in:)