Python regex for fixed character length

Question

I am new to regex am trying to create a simple regex. I have gotten below so far which works for the format I'm trying to test against.

import re
pattern = '^\+61-' #to ensure that the given string starts with +61
x = re.search(pattern, '+61-457999999')
print(x)

Output:

<re.Match object; span=(0, 4), match='+61-'>

What I'd like to do next is to add the character count check. So I tried to add {} to the end of my pattern. But this doesn't seem to work. I tried various combinations:

Eg '^\+61-{1}' - seems to look for 1 number of occurrence of '+61-' at the beginning.

What would be an appropriate addition to the regex so:

1. The starting characters are always '+61-4'
2. The length of the given input is always 13

This sounds like a simple question but I was unable to find an exact matching answer for Python and the scenario described.

Answer 1

A general solution would be to match the length with a lookahead: (?=^.{13}$) . Full example:

>>> bool(re.search(r"(?=^.{13}$)^\+61-", '+61-457999999'))
True
>>> bool(re.search(r"(?=^.{13}$)^\+61-", '+62-457999999'))
False
>>> bool(re.search(r"(?=^.{13}$)^\+61-", '+61-4579999999'))
False
>>> bool(re.search(r"(?=^.{13}$)^\+61-", '+61-45799999'))
False

You could also be more precise and match the format, assuming digits after the - :

>>> bool(re.fullmatch(r"\+61-\d{9}", '+61-457999999'))
True
>>> bool(re.fullmatch(r"\+61-\d{9}", '+62-457999999'))
False
>>> bool(re.fullmatch(r"\+61-\d{9}", '+61-4579999999'))
False
>>> bool(re.fullmatch(r"\+61-\d{9}", '+61-45799999'))
False

Or use .{9} if you want to match anything for the remaining 9 characters after the starting substring.

The reason '^\+61-{1}' doesn't work is it's specifying 1 occurrence of the preceding character - . {1} is always implicit after every character so that's no different than '^\+61-' .

As an aside, always use raw strings r"" for regex patterns in Python.

As another aside, you're in Python so it's easy to check the string's length with len .