I need to get latest field based on another field in group by we have
Table "SchoolReview"
Id | SchoolId | Review | Point |
---|---|---|---|
1 | 1 | rv1 | 8 |
2 | 1 | rv2 | 7 |
3 | 2 | rv3 | 4 |
4 | 2 | rv4 | 7 |
5 | 3 | rv5 | 2 |
6 | 3 | rv6 | 8 |
I need to group by SchoolId and the inside group I need to get Review and Point from highest "Id" column.
I dont need "Id" coulmn but even if I get it for this solution its okay.
Result I am looking for shall look like this.
SchoolId | Review | Point |
---|---|---|
1 | rv2 | 7 |
2 | rv4 | 7 |
3 | rv6 | 8 |
Any one experienced in MS SQL Server can help in this regard?
You do not need to group the rows, you simply need to select the appropriate rows from the table. In this case, using ROW_NUMBER()
is an option:
Table:
SELECT *
INTO Data
FROM (VALUES
(1, 1, 'rv1', 8),
(2, 1, 'rv2', 7),
(3, 2, 'rv3', 4),
(4, 2, 'rv4', 7),
(5, 3, 'rv5', 2),
(6, 3, 'rv6', 8)
) v (Id, SchoolId, Review, Point)
Statement:
SELECT SchoolId, Review, Point
FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY SchoolId ORDER BY Id DESC) AS Rn
FROM Data
) t
WHERE Rn = 1
Result:
SchoolId Review Point
---------------------
1 rv2 7
2 rv4 7
3 rv6 8
Using sample data from other answer
SELECT *
INTO #Data
FROM (VALUES
(1, 1, 'rv1', 8),
(2, 1, 'rv2', 7),
(3, 2, 'rv3', 4),
(4, 2, 'rv4', 7),
(5, 3, 'rv5', 2),
(6, 3, 'rv6', 8)
) v (Id, SchoolId, Review, Point)
SELECT S.SchoolId,
S.Review,
S.Point
FROM #Data S
INNER JOIN
(
SELECT Id = MAX(S1.Id),
S1.SchoolId
FROM #Data S1
GROUP BY SchoolId
) X ON X.Id = S.Id AND X.schoolId = S.SchoolId
ORDER BY X.SchoolId
;
output
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