Define Python class member function with *args

Question

In Python how could I define a member function with an unknown number of parameters without using keyword arguments? Something like this:

class Foo:
    def speak(self, *args):
        ...

Answer 1

You can do just that pretty easily. Note that you can iterate through each element in args .

class Foo:
    def speak(self, *args):
        for arg in args:
            print(arg, end=" ")
            
bar = Foo()
bar.speak("Hello", "I", "am", "bar")

Output:

Hello I am bar