A RegEx to split by semicolon outside single or double quotes

Question

I need a JavaScript RegEx to split a string by semicolon outside single or double quotes.

Actually i'm using the following regex /(?;\B['"][^'"]*)?(?![^'"]*['"]\B)/gm that sadly doesn't cover every case.

What i need:

const string = `Lorem ipsum; "dolor sit; amet"; consectetur 'adipiscing; elit.' Fusce; sit amet ligula.; Phasellus in laoreet quam.`;

const resultArr = string.split(/THEREGEX/gm);

console.log(resultArr);
// ["Lorem ipsum", "\"dolor sit; amet\"", " consectetur 'adipiscing; elit.' Fusce", "sit amet ligula.", " Phasellus in laoreet quam."]

Answer 1

You may use this regex:

((?:[^;'"]*(?:"(?:\\.|[^"])*"|'(?:\\.|[^'])*')[^;'"]*)+)|;

RegEx Demo

Code:

 const s = `Lorem ipsum; "dolor sit; amet"; consectetur 'adipiscing; elit.' Fusce; sit amet ligula.; Phasellus in laoreet quam.` const re = /((?:[^;'"]*(?:"(?:\\.|[^"])*"|'(?:\\.|[^'])*')[^;'"]*)+)|;/ console.log( s.split(re).filter(Boolean) )

RegEx Details:

• ( : Start capture group #1
  • [^;'"]* : Match 0 or more any character that are not ' and " and not ;
  • (?: : Start non-capture group
    • "(?:\\.|[^"])*" : Match a double quoted substring ignoring all escaped quotes
    • | : OR
    • '(?:\\.|[^'])*' : Match a single quoted substring ignoring all escaped quotes
  • ) : End non-capture group
  • [^;'"]* : Match 0 or more any character that are not ' and " and not ;
• ) : End capture group #1
• | : OR
• ; : Match a ;
• .filter(Boolean) : is used to remove empty results from split array