Function must return a list of the smallest even integers that are greater than or equal to, sorted into ascending order

Question

Python: List of Even Integers, implement a function that:

1. Is named even
2. takes 2 Integer arguments, start, and n.
3. returns a list of n smallest even integers greater than or equal to start in ascending order.

Implementation of the function will be tested by a provided code stub on several input files. Each input file contains parameters for the function call. The function will be called with those parameters, and the result of its execution will be printed to the standard output by the provided code.

Constraints

• 1 <= start, n <= 100

Input Format Format for Custom Testing

In the first and only line, there are two space separated integers, start, and n.

Sample Case 0

Sample Input

STDIN Function 2 4 start = 2, n = 4

Sample Output

2 4 6 8

Explanation The function must return a list of the 4 smallest even integers that are greater than or equal to 2, sorted into ascending order: 2,4,6, and 8.

Below is my code so far, but it only prints the even number within the range of the list not the length which is mentioned in the list:-

def even(start, n):
    count = []

    for i in range(start, n):
        if 1 <= start and n <= 100:
            if i % 2 == 0:
                count.append(i)
    return [count]

start = int(input("Enter the number where the even should start from:  "))
n = int(input("Enter the value of length you want to show the even numbers of: "))
print(even(start, n))

Answer 1

I believe you're running into trouble when in the range declaration.

for i in range(start, n):

This could probably be rewritten to range(start, start + n) . With some changes to your loop logic, this reasoning will get you there.

A different approach to this problem could be to determine whether of not the start val is even or not and then adding even numbers to it. In the solution below, the meaning of length is more clearly represented.

def even(start, n): 
    count = []
        
    # Check if start is even
    if start % 2 != 0:
        start = start + 1 
        
    # A set of even numbers can be thought of the set of all numbers multiplied by 2                                                                                                                                                                                                                                           
    for i in range(0, n): 
        count.append(start + i*2)   
    return count

start = int(input("Enter the number where the even should start from:  "))
n = int(input("Enter the value of length you want to show the even numbers of: "))
print(even(start, n))

Answer 2

Your code is mostly wrong. Do it like this:

def even(start, n):
    if start % 2:
        start += 1 # If odd, start from the next even
    return [x for x in range(start, start+2*n+1, 2)]

Answer 3

def even(start, n):
    if start % 2:
        start += 1 # If odd, start from the next even
    return [x for x in range(start, start + 2 * n, 2)]

start = int(input("Enter the number where the even should start from:  "))
n = int(input("Enter the value of length you want to show the even numbers of: "))
print(even(start, n))

Answer 4

Your code is almost ok. You only need a few changes in this part.

for i in range(start, start+2*n):
    
        if i % 2 == 0:
            count.append(i)
return count