With the regular expression \\s{2}\\b
I'm trying to replace the last two whitespaces before a word with a pipe (|)
using a Word Boundary, but it's ignoring the number -18.055,81
. With what kind of expression I can also get the last two whitespaces before -18.055,81
?
Example:
1234 - This is a test 18.055,81 -18.055,81 0,00 0,00 18.055,81
Results in:
1234 - This is a test |18.055,81 -18.055,81 |0,00 |0,00 |18.055,81
What I want:
1234 - This is a test |18.055,81 |-18.055,81 |0,00 |0,00 |18.055,81
You can use
\s{2}(?=-?\d)
\s{2}(?=-?\w)
See the regex demo . Details:
\\s{2}
- two whitespace chars (?=-?\\d)
- that are immediately followed with an optional hyphen and then a digit. If there are any other word chars expected (letters, or underscores), replace \\d
with \\w
.
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