void main()
{
int a[][4]={ 5,7,5,9,
4,6,3,1,
2,9,0,6};
int *p;
int *q [4];
p=(int *)a;
q=a;
printf("\n %u %u",p,q);
p++;
q++;
printf("\n %u %u",p,q);
}
My query is can we assign 2-D array to the array of pointers. The above code shows error as 1.c: In function 'main': 1.c:14:6: error: assignment to expression with array type
In C language, arrays are not first class citizens:
If q
is an array of pointer, the answer is no, you cannot assign to an array.
If you want q
to be a pointer to arrays , you must declare it as int (*q)[4];
:
int(*q)[4];
q = a;
You can then use it to access elements of a
: q[i][j]
is the same as a[i][j]
(and q[i]
the same as q[j]
)
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