how to use input function in multiple if statement

Question

hi beginner here I'm learning if statement
this my code

print("Welcome to the dungeon.")
print("Your mission is to find the ursine sword.") 

level_1 = input("there is two doors infront of you type 'right' for the right door and 'left' for the left door.\n" )
level_1.lower()
if level_1 == "right" :
  print("this door is closed your level is too low to open it.\n")
if level_1 == "left" :
 level_2 = input("you found a two ladder one leads to upstairs type 'upstairs' and another leads to the basement type 'basement'.\n ")
level_2.lower()

if level_2 == "basement" :
   print("hisssssss ,  you got bitten by snake game over")
if level_2 == "upstairs" :
  level_3 =int(input("it seems like the final room thre is three swords infront of you two of them must be traps chose '1','2' or '3' "))
if level_3 == 1 :
  print("you released a powerful ghost you'r dead")
elif level_3 == 3 :
  print("you opened a portal to a cater you're dead")
elif level_3 == 2 :
  print("congratulations you found the ursine sword")
else :
  print("game over.")

I tried many other ways to use input but can't describe it the issue is level_2 is undefined when i choose 'right' but if i choose 'left' the code continue with no problem and i can choose 'upstairs' with no issue and continue with level_3 and can choose form 1,2,3 with no issue even though level_3 is inputted like level_2 or am I wrong? #new code

print("Welcome to the dungeon.")
print("Your mission is to find the ursine sword.") 

print("Welcome to the dungeon.")
print("Your mission is to find the ursine sword.") 
level_1 = input("there is two doors infront of you type 'right' for the right door and 'left' for the left door.\n")
if level_1== "right":
  print("this door is closed your level is too low to open it.\n")
elif level_1== "left":
  level_2 =input("you found a two ladder one leads to upstairs type 'upstairs' and another leads to the basement type 'basement'.\n ").lower()
  if level_2== "basement":
    print("hisssssss ,  you got bitten by snake game over")
  elif level_2== "upstairs":
    level_3 = int(input("it seems like the final room thre is three swords infront of you two of them must be traps chose '1','2' or '3' "))
    if level_3 == 1 :
     print("you released a powerful ghost you'r dead")
    elif level_3 == 3 :
     print("you opened a portal to a cater you're dead")
    elif level_3 == 2 :
     print("congratulaitons you found the ursine sword")
else :
  print("game over.")

this the new code the indentation fixed my issue

Answer 1

Your level_2 is only defined if level_1 is 'left'. If it's not left then level_2 is not defined at all which throws the error.

Imagine if my level_1 is not "left", then when I get to the line which says level_2.lower() then python doesn't know what the value of level_2 is because it's never defined so it can't run the .lower() function

What you have to do is assign an initial value to level_2 before the if checks begin so that you dont get that error

level_2 = ""

level_1 = input("there is two doors infront of you type 'right' for the right door and 'left' for the left door.\n" )
level_1.lower()
if level_1 == "right" :
  print("this door is closed your level is too low to open it.\n")
if level_1 == "left" :
 level_2 = input("you found a two ladder one leads to upstairs type 'upstairs' and another leads to the basement type 'basement'.\n ")
level_2.lower()

Answer 2

The problem is that level_2 is only being given a value if you choose left in level_1 . If you choose right, it prints this door is closed your level is too low to open it. but then level_2 stays undefined so it raises the error. You could do the above answer, or you could add a while loop that runs until level_1 is left.

print("Welcome to the dungeon.")
print("Your mission is to find the ursine sword.")

level_1 = ''
while level_1 != 'left':
 level_1 = input("there is two doors infront of you type 'right' for the right door and 'left' for the left door.\n")
 level_1.lower()
 if level_1 == 'right':
    print("this door is closed your level is too low to open it.\n")
 else:
     pass

level_2 = input("you found a two ladder one leads to upstairs type 'upstairs' and another leads to the basement type 'basement'.\n ")
level_2.lower()
if level_2 == "basement" :
    print("hisssssss ,  you got bitten by snake game over")
if level_2 == "upstairs" :
    level_3 =int(input("it seems like the final room thre is three swords infront of you two of them must be traps chose '1','2' or '3' "))
if level_3 == 1 :
    print("you released a powerful ghost you'r dead")
elif level_3 == 3 :
    print("you opened a portal to a cater you're dead")
elif level_3 == 2 :
    print("congratulations you found the ursine sword")
else :
    print("game over.")

Answer 3

You get an error because level_2 only gets defined when level_1 is "left". If level_1 is not "left", your code will continue to throw errors.

What you can do is run lower_2.upper() in the second if statement. That way you only call the upper method on lower_2 after its defined. For example,

if level_1 == "left" :
     level_2 = input("you found a two ladder one leads to upstairs type 'upstairs' and another leads to the basement type 'basement'.\n ")
     level_2.lower()