regex 2 numbers from a string

Question

How can I pull out the 2 numbers in-between Price Our: and the following | from this string?

"Delivery: Price => 30.00 - 45.00 | Price Our: 1900.00 => 1800.00 | Delivery: Contact => 3 - 4 Days | "

I tried (Price Our:.*?(?=\\|)) But thats the limit of my regex knowledge

Answer 1

You could use 2 capture groups:

\bPrice Our: (\d+(?:\.\d+)?) => (\d+(?:\.\d+)?) \|

The pattern matches:

• \\bPrice Our: A word boundary to prevent a partial match, then match Price Our:
• (\\d+(?:\\.\\d+)?) Capture group 1, match a number with an optional decimal part
• => Match literally
• (\\d+(?:\\.\\d+)?) Capture group 2, match a number with an optional decimal part
• \\| Match |

Regex demo

 const s = "Delivery: Price => 30.00 - 45.00 | Price Our: 1900.00 => 1800.00 | Delivery: Contact => 3 - 4 Days | "; const regex = /\\bPrice Our: (\\d+(?:\\.\\d+)?) => (\\d+(?:\\.\\d+)?) \\|/; const match = s.match(regex); if (match) { console.log(match[1]); console.log(match[2]); }

In case the digits are at the end of the string, and there is no | following, you can account for that using an alternation to assert the end of the string:

\bPrice Our: (\d+(?:\.\d+)?) => (\d+(?:\.\d+)?)(?: \||$)

Regex demo

Answer 2

(\\d*\\.\\d+)

regex101 explanation:

 const regex = /(\\d*\\.\\d+)/gm; const str = "Delivery: Contact => 3 - 4 Days | Price Our: 1900.00 => 1800.00 | Delivery: Contact => 3 - 4 Days | "; const res = str.match(regex) console.log(res)