Lets say I have a string like this:
String str = "~asdfl;kjx,~rgadfaeg,dsafnewgfljka;ldfjsfa;dlkjfa;lvjvbnaber;fwelfjadfafa"
int character = 12
What I want to do is delete every 12th character in the string, so i would delete the 12 index, then the 24th, then the 36th, etc until the string is over.
Which index I delete (every 12th, or every 2nd) has to equal the character variable I have, since that variable changes.
I tried doing this with regex:
System.out.println(s.replaceAll(".(.)", "$12"));
But it didnt work. any help?
Sometimes, a simple for
loop is all you need:
public class Test {
public static void main(String[] args) {
String str = "~asdfl;kjx,~rgadfaeg,dsafnewgfljka;ldfjsfa;dlkjfa;lvjvbnaber;fwelfjadfafa";
int character = 12;
StringBuilder sb = new StringBuilder();
for (int i = 0; i < str.length(); i++) {
if ((i + 1) % character != 0) {
sb.append(str.charAt(i));
}
}
String result = sb.toString();
System.out.println(result);
}
}
If you insist on using regular expressions, you can interpolate the character
variable into the expression as follows:
public class Test {
public static void main(String[] args) {
String str = "~asdfl;kjx,~rgadfaeg,dsafnewgfljka;ldfjsfa;dlkjfa;lvjvbnaber;fwelfjadfafa";
int character = 12;
System.out.println(str.replaceAll("(.{" + (character - 1) + "}).", "$1"));
}
}
To delete every 12th character using regex, use this pattern:
(.{11}).
And then replace with just the captured $1
.
Sample Java code:
String str = "~asdfl;kjx,~rgadfaeg,dsafnewgfljka;ldfjsfa;dlkjfa;lvjvbnaber;fwelfjadfafa";
String output = str.replaceAll("(.{11}).", "$1");
System.out.println(output);
This prints:
~asdfl;kjx,rgadfaeg,dsfnewgfljka;dfjsfa;dlkja;lvjvbnabe;fwelfjadfaa
Edit:
To do a regex replacement of some fixed width, use:
String str = "~asdfl;kjx,~rgadfaeg,dsafnewgfljka;ldfjsfa;dlkjfa;lvjvbnaber;fwelfjadfafa";
int width = 11;
String output = str.replaceAll("(.{" + width + "}).", "$1");
System.out.println(output);
char
The char
type in Java is legacy, essentially broken. As a 16-bit value, a char
is incapable of representing most characters.
Instead, use code point integers.
Make an array of each character's code point.
int[] codePointsArray = input.codePoints().toArray() ;
Make a list of that array.
List< Integer > codePoints = List.of( codePointsArray ) ;
Alternatively:
List< Integer > codePoints = input.codePoints().boxed().toList() ;
Make an IntStream
of the indexes we need to access each element of that list. Use each index to pull out a code point, and filter by the nth element. Collect into a StringBuilder
.
String result =
IntStream
.range( 0 , codePoints.size() )
.filter( n -> n % 12 != 0 )
.mapToObj( codePoints :: get )
.collect( StringBuilder :: new , StringBuilder :: appendCodePoint , StringBuilder :: append )
.toString()
;
That is untested code, but should be close to what you need.
My code here is based on what I saw on this similar Question .
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