Suppose that I have an array in no particular order, and I want to get all values of a given type from that array (for this example, let's use strings).
oldArray = [1, "2", {3: 4}, 5, "6", /7/];
/* ... */
newArray = ["2", "6"];
Logically, I would do something like this:
newArray = [];
oldArray.forEach((element) => {
if (typeof element === "string") {
newArray.push(element);
}
});
(Though it isn't as elegant as the Python one-liner [value for value in oldArray if type(value) == str]
, it still suffices for me.)
My question is: Is there a more efficient way to do this, or is this an optimal solution?
您可以使用array.filter()
:
newArray = oldArray.filter(e => typeof e == "string")
Using Array#filter
and typeof
:
const oldArray = [1, "2", {3: 4}, 5, "6", /7/]; const newArray = oldArray.filter(e => typeof e === 'string'); console.log(newArray);
我认为这是最简单的你会得到🤣
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