Remove digit from given integer

Question

I have a homework problem. I need to write a function that receives a positive integer and a digit. This function removes all the digits as same is the given digit from the number.

Example for the function:

removeDigit(78452813, 8) => 745213 (removes all 8)

This is my code:

enter image description here

Code in text:

def removeDigit(num,digit):
    temp=0
    while num>0:
        remDigit=num % 10
        num=int(num / 10)
        if remDigit != digit:
            temp=temp * 10 + remDigit
        else:
            continue
    return temp

My function deletes the digit, but it returns the new number reversed.

Does anyone knows how to fix this?

Answer 1

there are many ways to solve this problem, here is one: instead of

temp = temp * 10 + rem_digit

you can do

temp = temp / 10 + rem_digit

in this case the order is preserved.
now you just need to make it an integer again:

while not temp.is_integer():
    temp *= 10
return int(temp)

Answer 2

Have you tried converting the number to a string and using string.replace()? I'm not going to do your homework for you but that should be a good place to start.

Answer 3

You could try a recursive approach:

def remDigit(N,S):
    n,d = divmod(N,10)
    return 0 if not N else remDigit(n,S) if d==S else remDigit(n,S)*10+d 

r = remDigit(78452813, 8)
print(r)
745213