So I am dealing with an object that looks a bit like this:
{
examples: [
{ key: 'value1' },
{ key: 'value1' },
{ key: 'value1' },
{ key: 'value2' },
{ key: 'value2' },
{ key: 'value2' }
]
}
As you can see the values are ordered. I'm trying to get where the value is value2 and I'm sure there is a more efficient way than what I am doing currently, as the actual object is significantly larger and so it takes some time to reach value2. This is the function I created:
function getValue2 (obj, num) {
if (obj.examples[num] = "value2"){
console.log(obj.examples[num]);
}
else {
getValue2(obj, num + 1);
};
};
var x = JSON.parse(obj);
getValue2(x, 0);
Thank you in advance! :)
You can use Array#find
:
returns the value of the first element in the provided array that satisfies the provided testing function. If no values satisfy the testing function, undefined is returned.
const data = { examples: [ { key: 'value1' }, { key: 'value1' }, { key: 'value1' }, { key: 'value2' }, { key: 'value2' }, { key: 'value2' } ] }; const res = data.examples.find(({ key }) => key === 'value2'); console.log(res);
How about using Object.values , like this:
function getValue2(obj){
return Object.values(obj.examples).find(e => e === 'value2')
}
The first problem I see is you are using a single equals =
to check equality when it should be ==
or ===
.
As for alternative ways to run a similar function, I suggest you look up and learn about the for
and while
loops, as they are essential for JS.
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