Nodejs - How to find the index with two conditions, one condition being where a property exists

Question

I have an object that looks like this:

{
   "examples":[
      {
         "key":"value1"
      },
      {
         "key":"value1",
         "key2":"example"
      },
      {
         "key":"value1"
      },
      {
         "key":"value2"
      },
      {
         "key":"value2",
         "key2":"example"
      },
      {
         "key":"value2"
      }
   ]
}

I'm trying to use findIndex to find where in the object that key === 'value1' and key2 exists (so in this instance the index would be 1). I've tried using something like var x = examples.findIndex(({key}) => key === 'value1' && ({key2}) => key2) but it's not working. How do I go about this? Any answers would be greatly appreciated! :)

Answer 1

examples is a property of the data object, so you need to iterate over that array. examples.findIndex won't do anything.

You can then check to see if key has "value1" as a value, and that there is a key2 in the object.

 const data={examples:[{key:"value1"},{key:"value1",key2:"example"},{key:"value1"},{key:"value2"},{key:"value2",key2:"example"},{key:"value2"}]}; const result = data.examples.findIndex(obj => { return obj.key === 'value1' && obj.key2; }); console.log(result);