Compare two arrays of objects; If second object contains the same key/value as the first return the second's, if not add key/value from the first

Question

Consider the following: We have two arrays, each with an object.

let users: [
  {
    "id": "some#"
    "name": "some name",
    "data": "somedata"
  }
],


let products: [
    {
      "product": "some#"
      "name": "abc",
    },
]

Essentially compare both objects, if the second object has the same property as the first, keep the second prop and value if not add the prop/value from the first.

So the output is :

{
  "id": "some#",
  "name": "abc",
  "data": "somedata"
}

Answer 1

Try this:

if (!(users[0].name === products[0].name)) {
product[0].data = users[0].data
}

Answer 2

With the code below, for the data you have given, you can have that output you are looking for:

 let users = [ { id: "some#", name: "some name", data: "somedata" } ]; let products = [ { product: "some#", name: "abc" } ]; for (key in users[0]) { if (products[0][key]) { users[0][key] = products[0][key]; } else { continue; } } console.log(users);