public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter number: ");
int a = sc.nextInt();
for ( int i = 1; i < a; i++) {
int []div = {a/i};
if (a%i == 0 ) System.out.print(Arrays.toString(div) + " ");
}
}
Input: 68 Output : [68] [34] [17] [4] [2]
Question is how to make a single array so it looks like [68, 34, 17, 4, 2] ?
Since you can't calculate how many elements the div
will have in advance (it requires factorization of a
), you have several options:
div
as a separate step: int a = 68;
int n = 0; // length of the result
for (int i = 1; i < a; i++) {
if (a % i == 0) {
n++;
}
}
int[] div = new int[n];
n = 0;
for (int i = 1; i < a; i++) {
if (a % i == 0) {
div[n++] = a / i;
}
}
System.out.println(Arrays.toString(div));
int a = 68;
List<Integer> div = new ArrayList<>();
for (int i = 1; i < a; i++) {
if (a % i == 0) {
div.add(a / i);
}
}
System.out.println(div);
If you need, you can convert the collection to the primitive array afterwards:
int[] divArr = div.stream().mapToInt(Integer::intValue).toArray();
System.out.println(Arrays.toString(divArr));
Stream
: As @Eritrean
suggested in the comments, you can use IntStream
to build your array:
int a = 68;
int[] div = IntStream
.range(1, a)
.filter(i -> a % i == 0)
.map(i -> a / i)
.toArray();
System.out.println(Arrays.toString(div));
It will be more efficient than the second variant, as it avoids creating Integer
wrappers.
PS I omitted main
method and Scanner
initialization for brevity. You can put it back, if you need, for example:
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter number: ");
int a = sc.nextInt();
int n = 0; // length of the result
for (int i = 1; i < a; i++) {
if (a % i == 0) {
n++;
}
}
int[] div = new int[n];
n = 0;
for (int i = 1; i < a; i++) {
if (a % i == 0) {
div[n++] = a / i;
}
}
System.out.println(Arrays.toString(div));
}
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