I would like to extract a list of words that fall specific after the word "as " (space after as) from the current string.
"Select s.BOOK_ID as bookID,s.first_name as firstName, s.last_name as lastName , b.book_name as bookName , b.price as price FROM STUDENTS s JOIN BOOKS b ON b.ID = s.BOOK_ID";
so I will return a list of string firstName lastName bookName price
You need to use the following regex: as (\w+)
See an example and its explanation on regex101 .
The sample code is:
Matcher matcher = Pattern.compile("as (\\w+)")
.matcher("Select s.BOOK_ID as bookID,s.first_name as firstName, s.last_name as lastName , b.book_name as bookName , b.price as price FROM STUDENTS s JOIN BOOKS b ON b.ID = s.BOOK_ID");
List<String> results = new ArrayList<String>();
while (matcher.find()) {
results.add(matcher.group(1));
}
System.out.println(results);
You can run it here .
Here it can be very nice to use regex, If you don't know what regex is, check out https://regexone.com/
https://betterprogramming.pub/introduction-to-regex-8c18abdd4f70
Here are some code that can solve this problem
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import java.util.*;
class Main{
public static void main(String[] args) {
String s = "Select s.BOOK_ID as bookID,s.first_name as firstName, s.last_name as lastName , b.book_name as bookName , b.price as price FROM STUDENTS s JOIN BOOKS b ON b.ID = s.BOOK_ID";
Pattern pattern = Pattern.compile("as (\\w+)"); //this is the regex pattern
Matcher matcher = pattern.matcher(s); //this tries to match your string with the pattern
ArrayList<String> arr = new ArrayList<>(); //arraylist to store the result
while (matcher.find()) { //this makes it loop over all the matches it finds.
arr.add(matcher.group(1)); //adds the SECOND match to the group. Try removing the number 1 and see the result after.
}
System.out.println(arr);
}
}
If you have any questions, ask away! Regex can be kinda scary in the start
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