CODE
import openpyxl
wb = openpyxl.open('the path to the file')
wb.active = 1
ws = wb.active
for row in ws.iter_rows('B4:F4'):
for cell in row:
if cell.value == "Maria":
print(ws.cell(row=cell.row, column=2).value)
Mistake: for row in range(min_row, max_row + 1):
TypeError: 'str' object cannot be interpreted as an integer
I need search "Pavel" and print it in console
Where is the mistake?
It looks like the method iter_rows
in the library has changed, refer to this answer:
How we can use iter_rows() in Python openpyxl package?
it might seem clearer to iterate the rows/columns by integers:
import openpyxl
wb = openpyxl.open('./test-2.xlsx')
ws = wb.active
# row 4
for row in range (4, 5):
# column B ~ column F
for column in range (2, 7):
cell = ws.cell(row, column)
if cell.value == "Pavel":
print(ws.cell(row=cell.row, column=column).value)
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