Well I have a problem using a function to write a string into a txt file, I just can't see why I can't print the string, when the program is in the function it just stop working. This is the code creating a function passing the value by reference of the file and it works perfectly:
void saveTXT(FILE** txt,char *string)
{
fputs(string,*txt);
}
int main()
{
FILE * doc;
char string [10], singleline[50];
printf("Write the name of the file: \n");
scanf("%s",string);
fflush(stdin);
printf("Write the string to save into the file:\n");
scanf("%[^\n]",singleline);
doc = fopen(string,"w");
saveTXT(&doc,singleline);
fclose(doc);
return 0;
}
But when I go back to my project that has the same logic the program just closes:
void saveTXT(FILE** txt,node* n)
{
char buffer[100];
if(n == NULL)
fprintf(*txt,"*\n");
else
{
strcat(strcpy(buffer,n->data),"\n");
fflush(stdin);
printf("This is the string to be saved: %s\n",buffer);
fputs(buffer,*txt); //Problem
saveTXT(&(*txt),n->right);
saveTXT(&(*txt),n->left);
}
}
I made sure to open the file before and close it later, what I print is the string to be saved in the file, it shows the string and then crash, I just don't know why that happens.
stdin
cannot be flushed. &(*txt) == txt
I think you struggle to understand what double pointers are for. You use them if you want to change the original pointer (single star one).
An example - the pointer fi
will be modified in the function weirdopen
:
void weirdopen(FILE **f, const char *filename)
{
*f = fopen(filename, "r");
}
void myread(FILE *f, char *str, const size_t size)
{
fgets(str, size, f);
}
int main(void)
{
FILE *fi;
char str[100];
weirdopen(&fi, "test.txt");
myread(fi, str, 100);
fclose(fi);
}
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