Parse string in python in dict

Question

I have a string after sql query like this: "['user_id=c370,'good_cnt=2','good_id=1999','igoodid=12341','good_id=1111','good_id=1214','good_id=1437']" Can I parse it not manually in dict: {'user_id': 'c370','good_cnt':2,'good_id': [1999, 12341, 1111, 1214, 1437]"

Answer 1

>>> from ast import literal_eval
>>> from urllib.parse import parse_qs
>>> literal_eval(s)
['user_id=c370', 'good_cnt=2', 'good_id=1999', 'igoodid=12341', 'good_id=1111', 'good_id=1214', 'good_id=1437']
>>> '&'.join(literal_eval(s))
'user_id=c370&good_cnt=2&good_id=1999&igoodid=12341&good_id=1111&good_id=1214&good_id=1437'
>>> parse_qs('&'.join(literal_eval(s)))
{'user_id': ['c370'], 'good_cnt': ['2'], 'good_id': ['1999', '1111', '1214', '1437'], 'igoodid': ['12341']}

Unless you have specific reasons not to use this, this seems like the sanest option. If you really want some values as single values and others as lists, you could post-process this:

>>> {k: v[0] if len(v) == 1 else v for k, v in parse_qs('&'.join(literal_eval(s))).items()}
{'user_id': 'c370', 'good_cnt': '2', 'good_id': ['1999', '1111', '1214', '1437'], 'igoodid': '12341'}

Or, to go for a complete different approach:

r = {}

for i in literal_eval(s):
    k, v = i.split('=')

    if k not in r:
        r[k] = v
    elif isinstance(r[k], list):
        r[k].append(v)
    else:
        r[k] = [r[k], v]

>>> r
{'user_id': 'c370', 'good_cnt': '2', 'good_id': ['1999', '1111', '1214', '1437'], 'igoodid': '12341'}