How can I make same result for re.findall and re.finditer on regular expressions?

Question

Topic

I would like to extract words or quotes with quotations without quotations using re.finditer() function rather than re.findall().

text = 'This is a very "sweet" and "beautiful" cake.'

-> ['sweet', 'beautiful']

output an issue

The re.finditer() function returns with quotations and I have no idea how to get rid of the top and bottom double quotations.

['sweet', 'beautiful']
['"sweet"', '"beautiful"']

Code

import re
text = 'This is a very "sweet" and "beautiful" cake.'
all = re.findall('"(.*?)"', text)
print(all)

all_obj = re.finditer('"(.*?)"', text)
result = []
for obj in all_obj:
    result.append(obj.group())
print(result)

What I have tried to do

Without stripping, is there any solution to fix this issue?

final_result = []
for word in result:
    final_result.append(word.rstrip('"').lstrip('"'))
print(final_result)

['sweet', 'beautiful']

Answer 1

Please use .group(1) to match and extract your group:

result.append(obj.group(1))